Finding Inverse of a matrix
Last updated at August 2, 2026 by Teachoo
Transcript
Ex 4.4, 3 Verify A (adj A) = (adj A) A = |š“| I, where A = [ā 8(2&3@ā4&ā6)] Let A = [ā 8(2&3@ā4&ā6)] adj A = [ā 8(2&3@ā4&ā6)] = [ā 8(ā6&ā3@4&2)] |š“| = |ā 8(2&3@ā4&ā6)| = 2 Ć (ā6) ā 3 Ć (ā4) = ā12 + 12 = 0 Calculating A (adj A) = [ā 8(2&3@ā4&ā6)] [ā 8(ā6&ā3@4&2)] = [ā 8(2 Ć(ā6)+3 Ć4&2 Ćā3+3Ć2@ā4 Ć(ā6)+(ā6) Ć4&ā4 Ć(ā3)+(ā6) Ć2)] = [ā 8(ā12+12&ā6+6@+ 24 ā24&12ā12)] = [ā 8(0&0@0&0)] Similarly (adj A)A = [ā 8(ā6&ā3@4&2)] [ā 8(2&3@ā4&ā6)] = [ā 8(ā 6(2)+(ā3) (ā4)&ā6(3)+(ā3)(ā6)@4(2)+2(ā4)&4 (3)+2 (ā6))] = [ā 8(ā12+12&ā18+18@8 ā 8&12ā12)] = [ā 8(0&0@0&0)] Also |A| I = 0I = O ā“ A (adj A) = (adj A)A = |A|I Hence Proved