- Suppose we want to lift a heavy box onto a platform (like a truck).
- There are 2 methods
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GIF Watch: example — Lifting a heavy box onto a truck
| Method | How | Force needed |
|---|---|---|
| Method 1 — Lift vertically | Lift the box straight up | Force F equal to its full weight — difficult if the box is too heavy |
| Method 2 — Push up a ramp | Place the box on a smooth inclined plank and push it up | Smaller force — but over a longer distance |
- Method 2 is easier — this sloping plank is an inclined plane .
- An inclined plane is a simple machine that helps move a heavy load to a higher (or lower) level .
- It is simply a sloping surface — a ramp.
- Take a smooth plank (say a cardboard piece) about 1.5 m long, a toy car (or cart), and a spring balance. Attach the spring balance to the cart. Arrange an elevated surface, such as the top of a low stool or a pile of books, at about 0.5 m height from the floor.
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GIF Watch: activity 7.3 — Let us experiment
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Step 1 — First, lift the cart vertically, slowly and steadily, from the floor to the top of the pile of books or stool, and note the reading of the spring balance scale.
- This reading is the force required to lift the cart vertically = weight of the cart.
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Step 2 — Next, place the plank against the top of the pile of books or stool. Pull the cart along the plank slowly and steadily.
- Is the reading of the spring balance (the force required) smaller than that of Step 1?
- Step 3 — Now, reduce the angle between the plank and the base (make the plank longer/less steep) and repeat Step 2. Observe how the force required changes as the plank becomes less steep.
- The force required to pull the cart up along the plank is smaller than lifting it vertically.
- As the plank becomes less steep , the force required decreases further.
- However, we have to apply the force over a larger distance to bring it to the same height.
- Let the mass of the object be m.
- Then the load = weight of the object = mg
- Let F′ be the force required to push the object up the plane — this is the effort.
- Let the length of the inclined plane = L, and the height to be reached = h.
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Work done by us on the object (along the ramp)
- Work = Force × Distance
- Work = F′ × L
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Potential energy gained by the object
- The object rises to height h.
- Potential energy gained = mgh
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Apply the work-energy theorem (ignoring friction)
- Work done by us = energy gained by the object
- F′ × L = mgh
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Rearranging
- mg / F′ = L / h
- Now, mg is the load and F′ is the effort.
- Mechanical advantage = Load / Effort = mg / F′
- Mechanical advantage of inclined plane = L / h
- The length of the ramp L is always larger than the height h.
- So L / h > 1 — mechanical advantage is greater than 1.
- This means the force F′ needed is less than the weight mg.
- By increasing L (making the ramp longer, with a shallower angle), the mechanical advantage L/h increases.
- So the effort F′ required becomes even smaller .
| Ramp | Force needed | Distance covered |
|---|---|---|
| Steep (short L) | Large | Small |
| Less steep (larger L) | Smaller | Larger |
| Very gentle (very large L) | Very small | Very large |
- Note — The work done, that is the product of force and displacement, is the same in all cases. If the force decreases, the displacement increases, thereby the work done remains constant.
- Height AB = 30 cm, width BC = 40 cm.
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Length of the ramp AC — by the right-angled triangle property (Pythagoras theorem)
- AC² = AB² + BC²
- AC² = 30² + 40² = 900 + 1600 = 2500
- AC = 50 cm
- Mechanical advantage = L / h
- MA = 50 / 30
- MA = 1.67
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🤔 Pause and Ponder 9 (from the book)
Explain why roads on hills are built to wind around in gentle slopes rather than going straight up?View answer
Answer- A winding road is like a longer inclined plane (larger L for the same height h).
- Larger L means larger mechanical advantage L/h.
- So vehicles need much less force to climb.
- Going straight up would need a very large force — engines would strain, and it would be unsafe.
- The trade-off — vehicles travel a longer distance, but the climb is easy.
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🤔 Pause and Ponder 10 (from the book)
To reach a higher floor, we find climbing an inclined ladder easier in comparison to climbing a vertical ladder (Fig. 7.30). Explain why.GIF Watch: what happens if we make the ramp longer
View answer
Answer- An inclined ladder acts like an inclined plane .
- Its length L is more than the height h — mechanical advantage L/h > 1.
- So less force is needed at each step compared to pulling our body straight up a vertical ladder.
- We cover a longer distance, but each step feels easier.
| Point | Detail |
|---|---|
| Inclined plane | Sloping surface to move loads up or down |
| Effort | F′, applied along the ramp |
| Load | mg, weight of the object |
| Mechanical advantage | L / h (always > 1, since L > h) |
| Longer ramp | Smaller force, larger distance |
| Work done | Same in all cases — force ↓, distance ↑ |
- Ramp trick — trade force for distance. Less force, more distance, same work.
- MA = L/h — just lengths, measure and divide.
- Hill roads wind for the same reason trucks use ramps — big L, small force.
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A ramp is 4 m long and reaches a height of 1 m. Find its mechanical advantage.
View Answer
- MA = L / h
- MA = 4 / 1
- MA = 4
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A box weighs 400 N. Using the ramp of Question 1 (MA = 4), how much effort is needed to push it up? (Ignore friction)
View Answer
- MA = Load / Effort
- 4 = 400 / Effort
- Effort = 400 / 4
- Effort = 100 N
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Does a longer ramp reduce the work needed to raise a box to the same height?
View Answer
- No. Work = mgh — it depends only on weight and height.
- A longer ramp reduces the force , not the work. The distance increases to compensate.
Key terms and units
| Term | Meaning |
|---|---|
| Inclined plane | Sloping surface (ramp) used as a simple machine |
| MA of inclined plane | Length of ramp / height = L/h |