# Misc. 15

Last updated at Dec. 8, 2016 by Teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Misc. 15 (Introduction) If A is square matrix such that A2 = A, then (I + A)3 – 7A is equal to A. A B. I − A C. I D. 3A In square matrix, Number of rows = Number of columns A is square matrix I is always a square matrix. Misc. 15 If A is square matrix such that A2 = A, then (I + A)3 -7A is equal to A. A B. I − A C. I D. 3A Given that A2 = A Finding (I + A)3 – 7A (I + A)3 – 7A Using (a + b)3 = a3 + b3 + 3a2b + 3ab2 = (I)3 + (A)3 + 3(I)2 A + 3(I)A2 – 7A = I + A3 + 3 I A + 3A2 I – 7A = I + A3 + 3A + 3A2 – 7A = I + A2 . A + 3A + 3A2 – 7A = I + A . A + 3A + 3A – 7A = I + A2 + 6A – 7A = I + A2 – A = I + A – A = I The correct answer is C

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CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .