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Ex 3.4

Ex 3.4, 1
Deleted for CBSE Board 2022 Exams

Ex 3.4, 2 Deleted for CBSE Board 2022 Exams

Ex 3.4, 3 Deleted for CBSE Board 2022 Exams

Ex 3.4, 4 Deleted for CBSE Board 2022 Exams

Ex 3.4, 5 Deleted for CBSE Board 2022 Exams

Ex 3.4, 6 Deleted for CBSE Board 2022 Exams

Ex 3.4, 7 Deleted for CBSE Board 2022 Exams

Ex 3.4, 8 Important Deleted for CBSE Board 2022 Exams

Ex 3.4, 9 Deleted for CBSE Board 2022 Exams

Ex 3.4, 10 Deleted for CBSE Board 2022 Exams

Ex 3.4, 11 Deleted for CBSE Board 2022 Exams

Ex 3.4, 12 Deleted for CBSE Board 2022 Exams You are here

Ex 3.4, 13 Deleted for CBSE Board 2022 Exams

Ex 3.4, 14 Deleted for CBSE Board 2022 Exams

Ex 3.4, 15 Important Deleted for CBSE Board 2022 Exams

Ex 3.4, 16 Deleted for CBSE Board 2022 Exams

Ex 3.4, 17 Important Deleted for CBSE Board 2022 Exams

Ex 3.4, 18 (MCQ) Deleted for CBSE Board 2022 Exams

Chapter 3 Class 12 Matrices (Term 1)

Serial order wise

Last updated at Sept. 24, 2018 by Teachoo

Ex3.4, 12 Find the inverse of each of the matrices, if it exists.[■8(6&−3@−2&1)] Let A =[■8(6&−3@−2&1)] We know that A = IA [■8(6&−3@−2&1)]= [■8(1&0@0&1)] A R1 →1/6 R1 [■8(𝟔/𝟔&(−3)/6@−2&1)] = [■8(1/6&0/6@0&1)] A [■8(𝟏&(−1)/2@−2&1)] = [■8(1/6&0@0&1)] A R2 →R2 + 2R1 [■8(1&−1/2@−𝟐+𝟐(𝟏)&1+2((−1)/2) )] = [■8(1/6&0@0+2(1/6)&1+2(0))] A [■8(1&−1/2@𝟎&0)] = [■8(1/6&0@1/3&1)] A Since we have all zeros in the second row of the left hand side matrix of the above equation. Therefore, A-1 does not exist.