![Ex 3.4, 9 - Find inverse [3 10 2 7] - Chapter 3 Matrices CBSE - Ex 3.4](https://d1avenlh0i1xmr.cloudfront.net/ca40f2ed-b559-4b13-83e7-0f096b437e03/slide22.jpg)
Introducing your new favourite teacher - Teachoo Black, at only ₹83 per month
Ex 3.4, 9 - Chapter 3 Class 12 Matrices (Term 1)
Last updated at May 29, 2018 by Teachoo
Chapter 3 Class 12 Matrices
Serial order wise
Transcript
Ex3.4, 9 Find the inverse of each of the matrices, if it exist [ 8(3&10@2&7)] Let A = [ 8(3&10@2&7)] We know that A = IA [ 8(3&10@2&7)]= [ 8(1&0@0&1)] A R1 R1 R2 [ 8( &10 7@2&7)]= [ 8(1 0&0 1@0&1)] A [ 8( &3@2&7)]= [ 8(1& 1@0&1)] A R2 R2 2R1 [ 8(1&3@ ( )&7 2(3))]= [ 8(1& 1@0 2(1)&1 2( 1))] A [ 8(1&3@ &7 6)]= [ 8(1& 1@0 2&1+2)] A [ 8(1&3@ &1)]= [ 8(1& 1@ 2&3)] A R1 R1 3R2 [ 8(1 3(0)& ( )@0&1)]= [ 8(1 3( 2)& 1 3(3)@ 2&3)] A [ 8(1 0& @0&1)]= [ 8(1+6& 1 9@ 2&3)] A [ 8(1& @0&1)]= [ 8(7& 10@ 2&3)] A I = [ 8(7& 10@ 2&3)] A This is similar to I = A-1 A Thus A-1 =[ 8(7& 10@ 2&3)]
