Last updated at March 11, 2017 by Teachoo

Transcript

Misc 2 Find the value of tan-1(tan〖7π/6〗 ) Let y = tan-1(tan〖7π/6〗 ) tan y =〖 tan〗〖7π/6〗 tan y = tan (210°) We know that range of principal value of tan-1 is (− 𝜋/2 , 𝜋/2 ) i.e. (− 90° ,90°) Hence y = 210° not possible Now, tan y = tan (210°) tan y = tan (180° + 30°) tan y = tan (30°) tan y = tan (30 × 𝜋/180) tan y = tan (𝜋/6) Hence, y = 𝜋/6 Which is in the range of principal value of tan-1 i.e. ((−π)/2, π/2) Hence, tan-1(tan〖3π/4〗 ) = y = 𝝅/𝟔

Chapter 2 Class 12 Inverse Trigonometric Functions

Ex 2.1, 5
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Ex 2.1, 8 Important

Ex 2.1, 12 Important

Ex 2.1, 14 Important

Example 5 Important

Example 8 Important

Ex 2.2, 12 Important

Ex 2.2, 15 Important

Ex 2.2, 19 Important

Ex 2.2, 21 Important

Example 10 Important

Example 12 Important

Example 13 Important

Misc. 2 Important You are here

Misc. 7 Important

Misc. 10 Important

Misc. 11 Important

Misc 12 Important

Misc. 17 Important

Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.