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Misc 6 - Three letters are dictated to three persons, an envelope - Using permutation

Misc 6 - Chapter 16 Class 11 Probability - Part 2


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Misc 6 Three letters are dictated to three persons and an envelope is addressed to each of them, the letters are inserted into the envelopes at random so that each envelope contains exactly one letter. Find the probability that at least one letter is in its proper envelope. Let the envelope be denoted by A, B, C and the corresponding letters are a, b, c The letters are inserted into the envelopes at random, & each envelope contain exactly one letter Possible combinations can be Aa Bb Cc Aa Bc Cb Ab Ba Cc Ab Bc Ca Ac Bb Ca Ac Ba Cb So, Total number of possible cases = 6 n(S) = 6 Let A be the event that at least one letter is in its proper envelope A = {(Aa, Bb, Cc), (Aa, Bc, Cb), (Ac, Bb, Ca), (Ab, Ba, Cc)} n(A) = 4 So, P(A) = n(A) n(S) = 4 6 =

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.