Miscellaneous

Chapter 16 Class 11 Probability
Serial order wise

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Transcript

Misc 3 A die has two faces each with number ‘1’, three faces each with number ‘2’ and one face with number ‘3’. If die is rolled once, determine P(2) A normal die has 6 faces 1, 2, 3, 4, 5, 6 But in this question die has following 6 faces 1, 1, 2, 2, 2, 3 n(S) = 6 We need to find P(2) There are 3 three 2’s Hence, n(2) = 3 So, P(2) = 𝑛(2)/(𝑛(𝑆)) = 3/6 = 𝟏/𝟐 Misc 3 A die has two faces each with number ‘1’, three faces each with number ‘2’ and one face with number ‘3’. If die is rolled once, determine (ii) P(1 or 3) Die has faces 1, 1, 2, 2, 2, 3 Now ,P (1 or 3) = P (1) + P(3) P(1) There are two 1’s Hence , n(1) = 2 P(1) = (𝑛(1))/(𝑛(𝑆)) = 2/6 P(3) There are only one 3’s Hence , n(3) = 1 P(3) = (𝑛(3))/(𝑛(𝑆)) = 1/6 Hence, P (1 or 3) = P (1) + P(3) = 2/6 + 1/6 = (2 + 1)/6 = 3/6 = 𝟏/𝟐 Misc 3 A die has two faces each with number ‘1’, three faces each with number ‘2’ and one face with number ‘3’. If die is rolled once, determine (iii) P(not 3) P(not 3) = 1 – P(3) For P(3) There is only one 3’s Hence , n(3) = 1 P(3) = (𝑛(3))/(𝑛(𝑆)) = 1/6 Hence, P(not 3) = 1 – P(3) = 1 – 1/6 = (6 − 1)/6 = 𝟓/𝟔

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.