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Misc 7 (ii) - Chapter 14 Class 11 Probability
Last updated at August 8, 2026 by Teachoo
Chapter 14 Class 11 Probability
Serial order wise
- Ex 14.1
- Ex 14.2
- Examples
-
Miscellaneous
- Sample Space
Transcript
Misc 7 A and B are two events such that P(A) = 0.54, P(B) = 0.69 and P(A ∩ B) = 0.35. Find (ii) P(A′ ∩ B′) P(A′ ∩ B′) = P(A ∪ B)′ = 1 − P(A ∪ B) = 1 − 0.88 = 0.12 (By Demorgan law) Demorgan’s law "(A’"∩"B’) = (A "∪" B)’" "or (A’ "∪" B’) = (A "∩" B)’"
