Last updated at May 29, 2018 by Teachoo

Transcript

Misc 4 In a certain lottery 10,000 tickets are sold and ten equal prizes are awarded. What is the probability of not getting a prize if you buy (a) one ticket Since, 1 ticket is chosen out of 10000 tickets n(S) = 10000C1 = 10000!1!9999! = 10000 × 9999!1 × 9999! = 10000 Now out of 10000 tickets only 10 have a prize Hence number of tickets not having prize = 10000 – 10 = 9990 Let A be the event that if we buy 1 ticket it does not have a prize Hence this 1 ticket will be out of 9990 ticket n(A) = 9990C1 = 9990!1! 9990 − 1! = 9990!1!9989! = 9990 × 9989!1 × 9989! = 9990 Probability not getting a prize if we get one ticket = P(A) = 𝑛(𝐴)𝑛(𝑆) = 999010000 = 𝟗𝟗𝟗𝟏𝟎𝟎𝟎 Misc 4 In a certain lottery 10,000 tickets are sold and ten equal prizes are awarded. What is the probability of not getting a prize if you buy (B) Two tickets 2 ticket is chosen out of 10000 ticket Hence n(S) = 10000C2 Let B be the event that if we buy two ticket it does not have a prize Hence this 2 ticket will be out of 9990 ticket n(B) = 9990C2 P(B) = 𝑛(𝐵)𝑛(𝑆) = 𝟗𝟗𝟗𝟎𝑪𝟐𝟏𝟎𝟎𝟎𝟎𝑪𝟐 Misc 4 In a certain lottery 10,000 tickets are sold and ten equal prizes are awarded. What is the probability of not getting a prize if you buy (C) 10 ticket 10 ticket is chosen out of 10000 ticket Hence n(S) = 10000C10 Let C be the event that if we buy 10 tickets it does not have prize Hence these 10 ticket will be out of 9990 ticket So, n(C) = 9990C10 P(C) = 𝑛(𝐶)𝑛(𝑆) = 𝟗𝟗𝟗𝟎𝑪𝟏𝟎𝟏𝟎𝟎𝟎𝟎𝑪𝟏𝟎

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.