# Example 3 - Chapter 12 Class 11 Introduction to Three Dimensional Geometry

Last updated at Dec. 8, 2016 by Teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Example 3 Find the distance between the points P(1, 3, 4) and Q ( 4, 1, 2). Given P (1, 3, 4) and Q ( 4, 1, 2) Distance PQ = x2 x1 2+ y2 y1 2+ z2 z1 2 Here, x1 = 1, y1 = 3, z1 = 4 x2 = 4, y2 = 1, z2 = 2 PQ = 4 1)2+(1 ( 3) 2+ 2 4 2 = 5)2+(1+3 2+ 2 2 = 25+ 4 2+4 = 45 = 3 3 5 = 3 5 units

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