Example 2 Find the octant in which the points (–3, 1, 2) and (–3, 1, – 2) lie. (−3, 1, 2) Here x is negative, y is positive and z is positive So it lies in II octant. (ii) (−3, 1, −2) Here x is negative, y is positive and z is negative. So it lies in VI octant.

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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