Question 1 - Page 49 - Pythagorean triples - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2)
Last updated at February 20, 2026 by Teachoo
Pythagorean triples
Pythagorean triples (Baudhāyana triples)
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Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2)
- Doubling a square
- Halving a square
- Hypotenuse of an Isosceles Right Triangle
- Decimal Representation of √2
- Figure it out - Page 39, 40
- Formula for Hypotenuse of an Isosceles Right Triangle
- Combining Two squares
- Baudhāyana’s Theorem on Right-angled triangles
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Pythagorean triples
- Figure it out - Page 50
- A Long-Standing Open Problem
- Further Applications of the Baudhāyana - Pythagoras Theorem
- Figure it out - Page 52, 53, 54
Transcript
Question 1 - Page 49 If (a, b, c) is a Baudhāyana triple, then (ka, kb, kc) is also a Baudhāyana triple where k is any positive integer. Is this statement true?This is always true Let’s prove it Proof Since (a, b, c) is a Baudhāyana triple Thus, a2 + b2 = c2 Now, we need to prove if (ka, kb, kc) is also a Baudhāyana triple Thus, we prove (ka)2 + (kb)2 = (kc)2 k2 × a2 + k2 × b2 = k2 × c2 k2 (a2 + b2) = k2 × c2 Since a2 + b2 = c2 k2 × c2 = k2 × c2 Since this is true, we can say that (ka, kb, kc) is also a Pythagorean Triple
