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Example 1 - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2)
Last updated at February 20, 2026 by Teachoo
Formula for Hypotenuse of an Isosceles Right Triangle
Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2)
- Doubling a square
- Halving a square
- Hypotenuse of an Isosceles Right Triangle
- Decimal Representation of β2
- Figure it out - Page 39, 40
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Formula for Hypotenuse of an Isosceles Right Triangle
- Combining Two squares
- BaudhΔyanaβs Theorem on Right-angled triangles
- Pythagorean triples
- Figure it out - Page 50
- A Long-Standing Open Problem
- Further Applications of the BaudhΔyana - Pythagoras Theorem
- Figure it out - Page 52, 53, 54
Transcript
Example 1 Find the hypotenuse of an isosceles right triangle whose equal sides have length 12.Our figure looks like Now, we know that π^π=ππ^π Putting values c^2=2 Γ (12)^2 c^2=2 Γ 144 c^2=288 π=βπππ Finding bounds We know that γππγ^π=258 (too small) γππγ^π=289 (too big) So, βπππ is between 16 and 17 We can write 16 < Hypotenuse (βπππ) < 17 The length of the hypotenuse of an isosceles right triangle, whose length of the equal sides is 12 units, is between 16 and 17 units.
