Question 14 - Arithmetic Progression - Chapter 8 Class 11 Sequences and Series

Last updated at Dec. 16, 2024 by

Ex 9.2, 14 - Insert five numbers between 8, 26 such that - Inserting AP between two numbers

Ex 9.2, 14 - Chapter 9 Class 11 Sequences and Series - Part 2

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Ex9.2,14 Insert five numbers between 8 and 26 such that the resulting sequence is an A.P. We know that to insert n numbers between a & b common difference (d) = ( )/( + 1) Here, We need to insert 5 numbers between 8 and 26 So, b = 26 , a = 8 & number of terms to be inserted = n = 5 Therefore, d = (26 8)/(5 + 1) = 18/6 = 3 Now, a = 8, d = 3 & b = 26 Hence five numbers between 8 and 26 are 11, 14, 17, 20 & 23

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