Ex 8.2,11
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 8.2,11 Prove that the coefficient of xn in the expansion of (1 + x)2n is twice the coefficient of xn in the expansion of (1 + x)2n–1 . We know that General term of (a + b)n is Tr + 1 = nCr an – r . br We have to prove coefficient of xn in (1 + x)2n = 2 × Coefficient of xn in (1 + x)2n – 1 i.e. 2nCn = 2 × 2n-1Cn
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Davneet Singh
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