# Ex 8.2, 4 - Chapter 8 Class 11 Binomial Theorem

Last updated at Dec. 8, 2016 by Teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Ex 8.2, 4 Write the general term in the expansion of (x2 yx)12, x 0 We know that General term of expansion (a + b)n is Tr+1 = nCr an r br For (x2 yx), Putting n = 12, a = x2 , b = yx Tr+1 = 12Cr (x2)12 r . ( yx)r = 12! ! 12 ! . (x)2(12 r) . ( 1)r . yr . xr = 12! ! 12 ! . x24 2r . ( 1)r . yr . xr = 12! ! 12 ! . x24 2r .xr . yr . ( 1)r = (-1)r . 12! ! 12 ! . (x)24 2r + r . yr = (-1)r . 12! ! 12 ! . x24 r . yr = (-1)r . 12Cr x24 r . yr Hence, General term = (-1)r . 12Cr x24 r . yr

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.