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Example 11 - Chapter 5 Class 11 - Solve 5x2 + x + 5 - Quadaratic equation

  1. Chapter 5 Class 11 Complex Numbers
  2. Serial order wise
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Example, 11 Solve √5x2 + x + √5 = 0 √5x2 + x + √5 = 0 The above equation is of the form π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐 = 0 where a = √5 , b = 1, and c = √5 x = (βˆ’π‘ Β± √( 𝑏^2 βˆ’ 4π‘Žπ‘ ))/2π‘Ž Putting values x = (βˆ’1 Β± √(1^2 βˆ’ 4 Γ— √(5 )Γ— √5) )/(2 Γ— √5) = (βˆ’1 Β± √(1 βˆ’ 4 Γ— 5))/(2√5) = (βˆ’1 Β± √(1 βˆ’ 20))/(2√5) = (βˆ’1 Β± √(βˆ’19))/(2√5) = (βˆ’1 Β± √19 Γ— √(βˆ’1))/(2√5) = (βˆ’1 Β± √19 𝑖)/(2√5) Thus, π‘₯ = (βˆ’1 Β± √19 𝑖)/(2√5)

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