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Example 1 - Chapter 5 Class 11 Complex Numbers (Term 1)
Last updated at March 22, 2023 by Teachoo
Examples
Example 1
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Example 2 (i)
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Example 3
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Example 5 Important
Example 6 (i)
Example 6 (ii) Important
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Example 12
Example 13 (i) Important
Example 13 (ii)
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Example 15
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Transcript
Example 1 If 4x + i(3x β y) = 3 + i (β6), where x and y are real numbers, then find the values of x and y. Given 4π₯ + π (3π₯ β π¦) = 3 + π (β6) Comparing Real Part 4π₯ = 3 π = π/π Comparing Imaginary Part 3π₯ β π¦ = β6 Putting π = π/π 3(π/π) β π¦ = β6 9/4βπ¦=β6 9/4+6=π¦ π=ππ/π Hence, π = π/π & π = ππ/π is the solution of the given equation
