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Example 5 - Find multiplicative inverse of 2 - 3i - CBSE - Division

Example 5 - Chapter 5 Class 11 Complex Numbers - Part 2


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Example, 5 Find the multiplicative inverse of 2 – 3i. Multiplicative inverse of z = z – 1 Multiplicative inverse of z = 1/𝑧 Putting z = 2 – 3i multiplicative inverse of 2 – 3i = 1/(2 βˆ’3𝑖) Rationalizing = 1/(( 2 βˆ’ 3𝑖 ) ) Γ—(( 2 + 3𝑖 ))/(( 2 + 3𝑖 ) ) = (2 + 3𝑖)/(( 2 βˆ’ 3𝑖 ) (2 + 3𝑖 ) ) Using ( a + b ) ( a – b ) = a2 – b2 = (2 + 3𝑖)/(2 2 βˆ’( 3𝑖 )2) = (2 + 3𝑖)/(4 βˆ’9𝑖^2 ) Putting i 2 = -1 = (2 + 3𝑖)/(4 βˆ’9 Γ—βˆ’1) = (2 + 3𝑖)/(4 + 9) = (2 + 3𝑖)/13 = 2/13 + 3𝑖/13 Hence, Multiplicative inverse = 2/13+3𝑖/13

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.