Example 12 - Chapter 3 Class 11 Trigonometric Functions (Term 2)

Transcript

Example 12 Find the value of tan 13𝜋/12 tan (13 𝜋" " )/12 = tan ("π + " 𝜋/12) = tan 𝜋/12 = tan (𝜋/4−𝜋/6) Using tan (𝑥 – 𝑦) = (tan𝑥 − tan⁡y)/(1 + tan 𝑥 tan⁡y ) = (tan⁡〖 π/4〗 − tan π/6)/(1 + tan π/4 tan⁡〖 π/6〗 ) = (1 − 1/√3)/(1 + 1/( √3)) = (√3 − 1)/(√3 + 1) = (√3 − 1)/(√3 + 1) × (√3 − 1)/(√3 − 1) = (√(3 )− 1)2/(√3 + 1)(√3 − 1) = (3 + 1 − 2√3)/((√3)2 − (1)2) = (4 − 2√3)/(3 − 1) = 2 – √𝟑