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Example 11 - Chapter 3 Class 11 Trigonometric Functions (Term 2)

Last updated at Nov. 17, 2020 by

Finding value of sin 15 degrees [with Video] - Teachoo Maths

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Example 11 Find the value of sin 15°. sin 15° = sin (45° – 30°) = sin 45° cos 30° – cos 45° sin 30° = 1/√2 × √3/2 −1/√2 × 1/2 = 1/√2 ((√3 − 1)/2) = (√𝟑 − 𝟏)/(𝟐√𝟐) sin (x – y) = sin x cos y – cos x sin y Putting x = 45° y = 30°

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