(a) Predict the output of the code given below:
 
  s="welcome2cs"
 
 
  n = len(s)
 
 
  m=""
 
 
  for i in range(0, n):
 
 
  if (s[i] >= 'a' and s[i] <= 'm'):
 
 
  m = m +s[i].upper()
 
 
  elif (s[i] >= 'n' and s[i] <= 'z'):
 
 
  m = m +s[i-1]
 
 
  elif (s[i].isupper()):
 
 
  m = m + s[i].lower()
 
 
  else:
 
 
  m = m +'&'
 
 
  print(m)
 
Answer:
 
   
  
Output: sELCcME&Cc
Explanation:
The above code takes the string s and iterates through each character of the string and:
- If the character is between ‘a’ and ‘m’, it is changed to uppercase and appended to the string m.
- Else if the character is between ‘n’ and ‘z’, its preceding character in the string is appended to the string m.
- Else if the character is in upper case, it is changed to smaller case and appended to the string m.
- Else, if the character does not satisfy any of the above conditions, an ‘&’ symbol is appended to the string m.
The final string ‘m’ is then printed as output.
