Ex 12.2, 9
A brooch is made with silver wire in the form of a circle with diameter 35 mm. The wire is also used in making 5 diameters which divide the circle into 10 equal sectors as shown in figure. Find :
the total length of the silver wire required
Here,
Brooch is made with silver wire in the form of a circle.
Diameter of the brooch = 35 mm
Radius of brooch = 35/2 mm
Since wire is used in making 5 diameter & circle.
So,
Total wire is used = length of wire in circle + Wire used in 5 diameters
Length of wire in circle
Length of wire in circle = circumference of circle
= 2
= 2 22/7 35/2
= 22 5
= 110 mm
Silver wire used in 5 diameters = 5 Diameter of circle
= 5 35
= 175 mm
Now,
Total wire is used = length of wire in circle + Wire used in 5 diameters
= 110 + 175
= 285 mm
Ex 12.2, 9
A brooch is made with silver wire in the form of a circle with diameter 35 mm. The wire is also used in making 5 diameters which divide the circle into 10 equal sectors as shown in figure. Find :
(ii) the area of each sector of the brooch.
Since the wire divides the circle into 10 equal sectors
Area of each sector of the brooch
= 1/10 Area of all sectors of the brooch
Area of all sectors of the brooch = area of circle
= 2
= 22/7 (35/2)^2
= 22/7 35/2 35/2
= (11 5 35)/2
Area of each sector of the brooch
= 1/10 Area of all sectors of the brooch
= 1/10 (11 5 35)/2
= 385/4 mm2
Area of each sector = 385/4 mm2

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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