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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Ex 11.1, 2 Find the area of a quadrant of a circle whose circumference is 22 cm. Area of quadrant = 1/4× Area of circle = 𝟏/𝟒 × 𝜋r2 Now, we need to find r. It is given that Circumference = 2πr 22 = 2πr 22/2 = πr 11 = πr 11/𝜋 = r r = 𝟏𝟏/𝝅 r = 11/(22/7) r = 11 × 7/22 r = 𝟕/𝟐 cm Now, Area of quadrant = 1/4× Area of circle = 1/4 × 𝜋r2 = 𝟏/𝟒×𝟐𝟐/𝟕×(𝟕/𝟐)^𝟐 = 1/4×22/7×(7 × 7)/(2 × 2) = 1/2×11/1×7/4 = 77/8 cm2

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.