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Ex 12.2, 2 - Find area of a quadrant whose circumference is 22 - Ex 12.2

Ex 12.2, 2 - Chapter 12 Class 10 Areas related to Circles - Part 2

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Transcript

Ex 11.1, 2 Find the area of a quadrant of a circle whose circumference is 22 cm. Area of quadrant = 1/4 area of circle = 1/4 (" "r2 ) Now, we need to find r. It is given that Circumference = 2 r 22 = 2 r 22/2 = r 11 = r 11/ = r r = 11/ r = 11/(22/7) r = 11 7/22 r = 7/2 cm Now, area of quadrant = 1/4 area of circle = 1/4(" "r2) = 1/4 22/7 (7/2)^2 = 1/4 22/7 (7 7)/(2 2) = 1/2 11/1 7/4 = 77/8 cm2

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.