![Ex 10.2, 10 - Chapter 10 Class 10 Circles - Part 2](https://d1avenlh0i1xmr.cloudfront.net/8b2af5de-2d70-4bc5-be37-e390f2edde83/slide22.jpg)
Last updated at April 16, 2024 by Teachoo
Ex 10.2,10 Prove that the angle between the two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line-segment joining the points of contact at the centre. Given: A circle with center O. Tangents PA and PB drawn from external point P To prove: APB + AOB = 180 Proof: In quadrilateral OAPB OAP + APB + OBP + AOB = 360 Putting values of angles 90 + APB + 90 + AOB = 360 180 + APB + AOB = 360 APB + AOB = 360 180 APB + AOB = 180 Hence proved