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Ex 9.1, 5 - A kite is flying at a height of 60 m above - Ex 9.1

EX 9.1, 5 - Part 2


Transcript

Ex 9.1 , 5 A kite is flying at a height of 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60°. Find the length of the string, assuming that there is no slack in the string. Given that, Height at which kite is flying = 60 metre Hence, AB = 60 m Also, inclination of the string with the ground = 60° Hence, ∠ACB = 60° We have to find length of string, i.e., AC Here, AB is perpendicular to ground So, ∠ ABC = 90° In right triangle ABC sin C = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐶" " )/𝐻𝑦𝑝𝑜𝑡𝑒𝑛𝑢𝑠𝑒 sin C = 𝐴𝐵/𝐴𝐶 sin 60° = 60/AC √3/2 = 60/AC AC = 2/√3 × 60 AC = 120/√3 Multiplying √3 in both numerator and denominator AC = 120/√3 × √3/√3 AC = (120√3)/3 AC = 40√3 m Hence, Length of the string = AC = 40√3 metre

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.