Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Examples
Last updated at May 29, 2023 by Teachoo
Example 1 A tower stands vertically on the ground. From a point on the ground, which is 15 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 60Β°. Find the height of the tower. Let, the height of the tower be H meter. So, AB = H metre Distance of the point from the foot of the tower = 15m Hence, CB = 15m Angle of elevation = 60Β° β ACB = 60Β° Since tower is vertical to ground, So, β ABC = 90Β° Now, tan C = (ππππ πππππ ππ‘π π‘π πππππ" c " )/(ππππ ππππππππ‘ π‘π πππππ" " πΆ) tan C = (" " π΄π΅)/πΆπ΅ tan 60Β° = π΄π΅/πΆπ΅ β3 = π»/15 15β3 = H H = 15β3 Hence, height of the tower = H = 15β3 m