Ex 8.1, 6.jpg

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Teachoo ยท Class 10 Explore Class 10

Transcript

Ex 8.1, 6 If โˆ  A and โˆ  B are acute angles such that cos A = cos B, then show that โˆ  A = โˆ  B. cos A = (๐‘ ๐‘–๐‘‘๐‘’ ๐‘Ž๐‘‘๐‘—๐‘Ž๐‘๐‘’๐‘›๐‘ก ๐ด)/๐ป๐‘ฆ๐‘๐‘œ๐‘ก๐‘’๐‘›๐‘ข๐‘ ๐‘’ = ๐‘จ๐‘ช/๐‘จ๐‘ฉ Similarly, cos B = (๐‘ ๐‘–๐‘‘๐‘’ ๐‘Ž๐‘‘๐‘—๐‘Ž๐‘๐‘’๐‘›๐‘ก ๐ต)/๐ป๐‘ฆ๐‘๐‘œ๐‘ก๐‘’๐‘›๐‘ข๐‘ ๐‘’ = ๐‘ฉ๐‘ช/๐‘จ๐‘ฉ Now, given that cos A = cos B ๐ด๐ถ/๐ด๐ต = ๐ต๐ถ/๐ด๐ต AC = BC We know that in a triangle, angles opposite equal sides are equal โˆ B = โˆ ๐€ Hence proved.

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