Proving
Last updated at December 13, 2024 by Teachoo
Transcript
Ex 8.1, 6 If ā A and ā B are acute angles such that cos A = cos B, then show that ā A = ā B. cos A = (š ššš šššššššš” š“)/š»š¦ššš”ššš¢š š = šØšŖ/šØš© Similarly, cos B = (š ššš šššššššš” šµ)/š»š¦ššš”ššš¢š š = š©šŖ/šØš© Now, given that cos A = cos B š“š¶/š“šµ = šµš¶/š“šµ AC = BC We know that in a triangle, angles opposite equal sides are equal ā B = ā š Hence proved.