**
**

####
**
In
**
**
Δ
**
**
ABC, right angled at B. AB = 12 cm, BC = 5cm.
**

**
Find sin A, cos A, tan A, cosec A, sec A, cot A
**

First we draw the triangle

**
Step 1
: Finding sides of triangle
**

In right triangle ABC,

Using Pythagoras theorem

(Hypotenuse)
^{
2
}
= (Height)
^{
2
}
+ (Base)
^{
2
}

AC
^{
2
}
= AB
^{
2
}
+ BC
^{
2
}

AC
^{
2
}
= 122 + 52

AC
^{
2
}
= 144 + 25

AC
^{
2
}
= 169

AC = √169

AC = √(13 ×13) =√(13
^{
2
}
) = 13

Hence AC = 13 cm

So, our triangle becomes

**
Step 2
: Finding sin
A , cos
A, tan A
**

__
__

Now, let us find cosec, cot and tan