Ex 8.1, 4
Given 15 cot A = 8, find sin A and sec A.
15 cot A = 8
cot A = 8/15
Now,
tan A = 1/cot
= 1/(8/15)
= 15/8
Hence, tan A = 15/8
tan A = 15/8
( )/( ) = 15/8
/ =15/8
Let
BC = 15x
& AB = 8x
Finding AC using Pythagoras theorem,
(Hypotenuse)2 = (Height)2 + (Base)2
AC2 = AB2 + BC2
AC2 = (8x)2 + (15x)2
AC2 = 64 x2 + 225 x2
AC2 = 289 x2
AC = 17x
Now, we need to find sin A & sec A

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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