The point on the x – axis which is equidistant from points (−1, 0) and (5, 0) is

(A) (0, 2) 

(B) (2, 0)

(C) (3, 0) 

D) (0, 3)

 

This question is similar to Ex 7.1, 7 - Chapter 7 Class 10 Coordinate Geometry

MCQ (NCERT Exemplar) - The point on the x – axis which is equidistant - Past Year MCQ

part 2 - Question 3 - Past Year MCQ - Serial order wise - Chapter 7 Class 10 Coordinate Geometry
part 3 - Question 3 - Past Year MCQ - Serial order wise - Chapter 7 Class 10 Coordinate Geometry

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Question 3 The point on the x – axis which is equidistant from points (−1, 0) and (5, 0) is (A) (0, 2) (B) (2, 0) (C) (3, 0) (D) (0, 3) Let Given points be A (−1, 0) and B(5, 0) Since point is x- axis, it’s y- coordinate will be 0 So, let point be C(a, 0) Since, Point C is equidistant from A and B ∴ AC = BC √(( 𝑎−(−1)^2+(0−0)^2 ) = √(( 𝑎−5)^2+(0−0)^2 ) √(( 𝑎+1)^2+0^2 ) =√(( 𝑎−5)^2+0^2 ) √(𝑎^2+1^2+2(𝑎)(1)+0) =√(𝑎^2+5^2−2(𝑎)(5)+0) √(𝒂^𝟐+𝟏^𝟐+𝟐𝒂) =√(𝒂^𝟐+〖𝟐𝟓〗^𝟐−𝟏𝟎𝒂) Squaring both sides 𝑎^2+1+2𝑎=𝑎^2+25−10𝑎 1+2𝑎=25−10𝑥 2𝑎+10𝑎=25−1 12𝑎=24 𝑎=24/12 𝒂=𝟐 ∴ Required point is (2, 0) So, the correct answer is (B)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo