Example 15 - Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
Last updated at May 29, 2018 by Teachoo
Transcript
Example 15 The height and the slant height of a cone are 21 cm and 28 cm respectively. Find the volume of the cone. Volume of the come = 1/3 ๐๐2โ Given slant height = l = 28 cm Height of cone = h = 21 cm Let radius of cone = r cm We know that l2 = h2 + r2 282 = 212 + r2 282 โ 212 = r2 r2 = 282 โ 212 r2 = (28 โ 21) (28 + 21) r2 = (7) (49) r = โ("7(49)" ) r = โ("7(7)2" ) r = 7โ7cm So, Volume of the come = 1/3 ๐๐2โ = 1/3 ร 22/7 ร 7 โ7 ร 7 โ7 ร 21 cm3 = 22 ร 7โ7 ร 7 โ7 cm3 = 22 ร 7 ร 7 ร(โ7)2 cm3 = 22 ร 7 ร 7 ร 7 cm3 = 7546 cm3
Examples
Example 1
Example 2 Important
Example 3
Example 4
Example 5
Example 6 Important
Example 7
Example 8 Important
Example 9
Example 10
Example 11 Important
Example 12
Example 13
Example 14 Important
Example 15 You are here
Example 16 Important
Example 17
Example 18 Important
Example 19
Surface Area and Volume Formulas Important
Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.