1. Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
  2. Serial order wise
  3. Ex 13.3

Ex 13.3, 1 - Chapter 13 Class 9 Surface Areas and Volumes (Term 2)

Last updated at May 29, 2018 by

Ex 13.3, 1 - Diameter of the base of a cone is 10.5 cm - Ex 13.3

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  1. Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
  2. Serial order wise

    3. Ex 13.3

    Ex 13.4 →

Transcript

Ex 13.3, 1 Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area. [๐ด๐‘ ๐‘ ๐‘ข๐‘š๐‘’ ๐œ‹=22/7] Curved Surface Area of cone of cone = ฯ€rl Radius (r) of the base of cone = (10.5/2) cm = 5.25 cm Slant height (l) of cone = 10 cm Curved Surface Area of cone of cone = ฯ€rl = (22/7ร—5.25ร—10) cm2 = (22/7ร—525/100ร—10) cm2 = ("22" ร—75/100ร—10) cm2 = 165 m2 Therefore, the curved surface area of the cone is 165 cm2.

Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
Serial order wise

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.