1. Chapter 13 Class 9 Surface Areas and Volumes
  2. Serial order wise
  3. Ex 13.3

Ex 13.3, 2 - Chapter 13 Class 9 Surface Areas and Volumes

Last updated at July 18, 2019 by

Ex 13.3, 2 - Find the total surface area of a cone - Area Of Cone

  1. Chapter 13 Class 9 Surface Areas and Volumes
  2. Serial order wise

    3. Ex 13.3

    Ex 13.4 →

Transcript

Ex 13.3, 2 Find the total surface area of a cone, if its slant height is 21 m and diameter of its base is 24 m. [๐ด๐‘ ๐‘ ๐‘ข๐‘š๐‘’ ๐œ‹=22/7] Total surface area of cone = ฯ€r(r + l) Radius (r) of the base of cone = (24/2) m = 12 m Slant height (l) of cone = 21 m Total surface area of cone = ฯ€r(r + l) = [22/7ร—12ร—(12+21)] m2 = (22/7ร—12ร—33) m2 = 1244.57 m2

Chapter 13 Class 9 Surface Areas and Volumes
Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.