Ex 2.3, 3 (iii) - Chapter 2 Class 9 Polynomials

Last updated at August 14, 2026 by

Ex 2.3, 3 - Find k, if (x - 1) is a factor of p(x) = kx^2 - √2x + 1 - Ex 2.3

part 2 - Ex 2.3, 3 (iii) - Ex 2.3 - Serial order wise - Chapter 2 Class 9 Polynomials

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Ex 2.3, 3 Find the value of k, if x 1 is a factor of p(x) in each of the following cases: (iii) p(x) = kx2 2 x + 1 Finding remainder when kx2 2x + 1 is divided by x 1 Step 1: Put Divisor = 0 x 1 = 0 x = 1 Step 2: Let p(x) = kx2 2x + 1 Putting x = 1 p(1) = k(1)2 2 (1) + 1 = k 2 + 1 Thus, Remainder = p(1) = k 2 + 1 Since x 1 is a factor of kx2 2x + 1 Remainder is zero, k 2 + 1 = 0 k = 2 1 Thus, k = 2 1

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