Ex 2.4,1 - Chapter 2 Class 9 Polynomials - Part 7

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Ex 2.4,1 - Chapter 2 Class 9 Polynomials - Part 8

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  1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise

Transcript

Ex 2.4, 1 Determine which of the following polynomials has (x + 1) a factor: (iv) x3 x2 (2 + 2) x + 2 Finding remainder when x3 x2 (2 + 2) x + 2 is divided by x + 1 Step 1: Put Divisor = 0 x + 1 = 0 x = 1 Step 2: Let p(x) = x3 x2 (2 + 2) x + 2 Putting x = 1 p( 1) = ( 1)3 ( 1)2 (2 + 2) ( 1) + 2 = 1 (1) + (2 + 2) + 2 = 1 1 + 2 + 2 + 2 = 2 + 2 + 2 + 2 = 2 2 Thus, Remainder = p( 1) = 2 2 Since remainder is not zero, x + 1 is not a factor of x3 x2 (2 + 2) x + 2

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.