Ex 2.4,1 - Chapter 2 Class 9 Polynomials - Part 5

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Ex 2.4,1 - Chapter 2 Class 9 Polynomials - Part 6

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  1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise

Transcript

Ex 2.4, 1 Determine which of the following polynomials has (x + 1) a factor: (iii) x4 + 3x3 + 3x2 + x + 1 Finding remainder when x4 + 3x3 + 3x2 + x + 1 is divided by x + 1 Step 1: Put Divisor = 0 x + 1 = 0 x = 1 Step 2: Let p(x) = x4 + 3x3 + 3x2 + x + 1 Putting x = 1 p( 1) = ( 1)4 + 3( 1)3 + 3( 1)2 + ( 1) + 1 = 1 3 + 3 1 + 1 = 1 Thus, Remainder = p( 1) = 1 Since remainder is not zero, x + 1 is not a factor of x4 + 3x3 + 3x2 + x + 1

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.