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Ex 2.3, 1 (ii) - Chapter 2 Class 9 Polynomials

Last updated at May 29, 2023 by

Ex 2.4,1 - Chapter 2 Class 9 Polynomials - Part 3

Ex 2.4,1 - Chapter 2 Class 9 Polynomials - Part 4

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Ex 2.3, 1 Determine which of the following polynomials has (x + 1) a factor: (ii) x4 + x3 + x2 + x + 1 Finding remainder when x4 + x3 + x2 + x + 1 is divided by x + 1 Step 1: Put Divisor = 0 x + 1 = 0 x = 1 Step 2: Let p(x) = x4 + x3 + x2 + x + 1 Putting x = 1 p( 1) = (-1)4 + ( 1)3 + ( 1)2 + ( 1) + 1 = 1 1 + 1 1 + 1 = 1 Thus, Remainder = p( 1) = 1 Since remainder is not zero, x + 1 is not a factor of x4 + x3 + x2 + x + 1

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.