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Last updated at Aug. 25, 2021 by Teachoo

Transcript

Ex 2.4, 3 Find the value of k, if x 1 is a factor of p(x) in each of the following cases: (ii) p(x) = 2x2 + kx + 2 Finding remainder when 2x2 + kx + 2 is divided by x 1 Step 1: Put Divisor = 0 x 1 = 0 x = 1 Step 2: Let p(x) = 2x2 + kx + 2 Putting x = 1 p(1) = 2(1)2 + k + 2 = 2 + k + 2 = 2 + 2 + k Thus, Remainder = p(1) = 2 + 2 + k Since x 1 is a factor of 2x2 + kx + 2 Remainder is zero, 2 + 2 + k = 0 k = 2 2 Thus, k = 2 2

Ex 2.4

Ex 2.4, 1 (i)
Important

Ex 2.4, 1 (ii)

Ex 2.4, 1 (iii)

Ex 2.4, 1 (iv) Important

Ex 2.4, 2 (i)

Ex 2.4, 2 (ii) Important

Ex 2.4, 2 (iii)

Ex 2.4, 3 (i)

Ex 2.4, 3 (ii) Important You are here

Ex 2.4, 3 (iii) Important

Ex 2.4, 3 (iv)

Ex 2.4, 4 (i)

Ex 2.4, 4 (ii) Important

Ex 2.4, 4 (iii)

Ex 2.4, 4 (iv) Important

Ex 2.4, 5 (i)

Ex 2.4, 5 (ii) Important

Ex 2.4, 5 (iii) Important

Ex 2.4, 5 (iv)

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.