Equal lengths of magnesium ribbons are taken in test tubes A and B. Hydrochloric acid (HCl) is added to test tube A, while acetic acid (CH 3 COOH) is added to test tube B. In which test tube will the fizzing occur more vigorously and why?

 

Answer

The two acids given are HCl and CH 3 COOH. HCl is a strong acid since it dissociates completely to produce H + ions.

HCl → H + + Cl

 

The single arrow in the above reaction shows that HCl is completely ionised.

 

On the other hand,

CH 3 COOH is a weak acid and does not dissociate completely.

CH 3 COOH ⇌ CH 3 COO - + H +

 

The double arrow pointing towards both left and right show that CH 3 COOH has not completely ionised.

 

Hence, when an equal length of Magnesium ribbon (a metal) is added to 2 test tubes,

The test tube in which HCl is added (Test Tube A) will show more fizzing because strong acids react more vigorously with Metals to produce salt and Hydrogen gas.

The chemical equation can be written as follows:

Mg(s) + H 2 SO 4 (aq) → MgSO 4 (aq) + H 2 (g)

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Hence, test tube A will show more fizzing.

  1. Class 10
  2. Chapter 2 Class 10 - Acids, Bases and Salts (Term 1)

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CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 11 years and a teacher from the past 11 years. He teaches Science, Accounts and English at Teachoo