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Transcript

Ex 8.2, 1 Evaluate the following : "5 cos2 60° + 4 sec2 30° – tan2 45°" /"sin2 30° + cos2 30°" We know that cos "60° = " 1/2 sec "30° = " 1/cos⁡〖30°〗 "= " 2/√3 tan "45°" = 1 sin "30° = " 1/2 cos "30°" = √3/2 Now, (𝟓 𝒄𝒐𝒔𝟐 𝟔𝟎°+ 𝟒 𝒔𝒆𝒄𝟐 𝟑𝟎°−𝐭𝐚𝐧𝟐⁡〖𝟒𝟓°〗)/(𝒔𝒊𝒏𝟐 𝟑𝟎° + 𝒄𝒐𝒔𝟐 𝟑𝟎°) Putting values = (𝟓(𝟏/𝟐)^𝟐 + 𝟒(𝟐/√𝟑)^𝟐 − (𝟏)𝟐)/((𝟏/𝟐)^𝟐 + (√𝟑/𝟐)^𝟐 ) = (5/4 + 4 × ( 2 × 2)/(√3 × √3) − 1)/(1/4 + (√3 × √3)/(2 × 2)) = (𝟓/𝟒 + 𝟏𝟔/𝟑 − 𝟏)/(𝟏/𝟒 + 𝟑/𝟒) = ((5 × 3 + 16 × 4 − 1 × 4 × 3 )/(4 × 3) )/((1 + 3)/4 ) = ((15 + 64 − 12 )/(4 × 3) )/(4/4 ) = ((67 )/12 )/1 = 𝟔𝟕/𝟏𝟐 Hence, (𝟓 𝒄𝒐𝒔𝟐 𝟔𝟎°+ 𝟒 𝒔𝒆𝒄𝟐 𝟑𝟎°−𝐭𝐚𝐧𝟐⁡〖𝟒𝟓°〗)/(𝒔𝒊𝒏𝟐 𝟑𝟎° + 𝒄𝒐𝒔𝟐 𝟑𝟎°) = 𝟔𝟕/𝟏𝟐

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.