Question 1 (ii) - Area of Triangle when coordinates are given - Chapter 7 Class 10 Coordinate Geometry
Last updated at April 16, 2024 by Teachoo
Area of Triangle when coordinates are given
Area of Triangle when coordinates are given
Last updated at April 16, 2024 by Teachoo
Ex 7.3 , 1 Find the area of the triangle whose vertices are : (ii) (–5, –1), (3, –5), (5, 2) Let the two points be A(−5, −1) , B(3, −5) & C(5, 2) Area of triangle ABC = 1/2 [ x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)] Here x1 = −5 , y1 = −1 x2 = 3 , y2 = −5 x3 = 5 , y3 = 2 Putting values Area of triangle ABC = 1/2 [ (−5)(−5 − 2) + 3(2 – (−1)) + 5(−1 – (−5))] = 1/2 [ −5(−7) + 3(2 + 1 ) + 5(−1 + 5)] = 1/2 [ −5(−7) + 3(3) + 5(4) ] = 1/2 [ 35 + 9 + 20] = 1/2 [64] = 32 square units