Ex 4.3, 1 (iii) - Ex 4.3

Ex 4.3, 1 (iii) - Chapter 4 Class 10 Quadratic Equations - Part 2

Ex 4.3, 1 (iii) - Chapter 4 Class 10 Quadratic Equations - Part 3

  1. Chapter 4 Class 10 Quadratic Equations (Term 2)
  2. Serial order wise

Transcript

Ex 4.3 ,1 Find the roots of the following quadratic equations, if they exist, by the method of completing the square: (iii) 4x2 + 4โˆš3 ๐‘ฅ+3=0 4x2 + 4 โˆš3 ๐‘ฅ+3=0 Dividing whole equation 4 (4๐‘ฅ^2+ 4 โˆš3 ๐‘ฅ+ 3)/4=0/4 (4๐‘ฅ^2)/4 + (4 โˆš3)/4 x + 3/4=0 x2 + โˆš3 ๐‘ฅ+ 3/4 = 0 We know that (a + b)2 = a2 + 2ab + b2 Here, a = x & 2ab = โˆš3 ๐‘ฅ 2xb = โˆš3 ๐‘ฅ 2b = โˆš3 b = โˆš3/2 Now, in our equation x2 + โˆš3 ๐‘ฅ+3/4=0 Adding and subtracting (โˆš3/2)^2 x2 + โˆš3 ๐‘ฅ+3/4+(โˆš3/2)^2โˆ’(โˆš3/2)^2=0 x2 + โˆš3 ๐‘ฅ+(โˆš3/2)^2+3/4โˆ’(โˆš3/2)^2=0 (๐‘ฅ+โˆš3/2 )^2+3/4โˆ’(โˆš3/2)^2=0 (๐‘ฅ+โˆš3/2 )^2+3/4โˆ’3/4=0 (๐‘ฅ+โˆš3/2 )^2=0 (๐‘ฅ+โˆš3/2 )^2=02 Cancelling square both sides (๐‘ฅ+โˆš3/2 )^2= ยฑ 0 So, the root of the equation are x = (โˆ’โˆš3)/2 & x = (โˆ’โˆš3)/2

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.