Last updated at May 29, 2018 by Teachoo

Transcript

Example 2 Check whether the following are quadratic equations: (i) (x 2)2 + 1 = 2x 3 (x 2)2 + 1 = 2x 3 Using (a b)2 = a2 + b2 2ab (x2 + 4 4x) + 1 = 2x 3 x2 + 5 4x = 2x 3 x2 + 5 4x 2x + 3 = 0 x2 6x + 8 = 0 It is the form ax2 + b x + c = 0 Where, a = 1, b = 6, c = 8 Hence it is a quadratic equation . Example 2 Check whether the following are quadratic equations: (ii) x(x + 1) + 8 = (x + 2) (x 2) x (x + 1) + 8 = (x + 2) (x 2) Using (a + b) (a b) = a2 b2 x (x + 1) + 8 = x2 4 x2 + x + 8 = x2 4 x2 + x + 8 x2 + 4 = 0 (x2 x2) + x + 8 + 4 = 0 x + 12 = 0 Since the highest power is 1 not 2 It is not in the form of 2 + + =0 It is not a quadratic equation . Example 2 Check whether the following are quadratic equations: (iii) x (2x + 3) = x2 + 1 x(2x + 3) = x2 + 1 2x2 + 3x = x2 + 1 2x2 + 3x x2 1 = 0 (2x2 x2) + 3x 1 = 0 x2 + 3x 1 = 0 It is the form of ax2 + bx + c = 0 Where a = 1, b = 3, c = 1 Hence, it is a quadratic equation . Example 2 Check whether the following are quadratic equations: (iv) (x + 2)3 = x3 4 (x + 2)3 = x3 4 Using (a + b)3 = a3 + b3 + 3a2b + 3ab2 x3 + 23 + 3 (x2) (2) + 3 (x) (2)^2 = x3 4 x3 + 8 + 6x2 + 12x = x3 4 x3 + 8 + 6x2 + 12 x x3 + 4 = 0 6x2 + 12x + 12 = 0 6(x2 + 2x + 2) = 0 x2 + 2x + 2 = 0 It is of the form ax2 + bx + c = 0 Where a = 1, b = 2, c = 2 Hence it is quadratic equation

Chapter 4 Class 10 Quadratic Equations

Concept wise

- Checking quadratic equation
- Making quadratic equation
- Solving by Splitting the middle term - Equation given
- Solving by Splitting the middle term - Statement given
- Solving by completing square
- Nature of roots
- Solving by quadratic formula - Equation given
- Solving by quadratic formula - Equation to be formed

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.