Learn all Concepts of Chapter 4 Class 10 (with VIDEOS). Check - Quadratic Equations - Class 10

Last updated at May 29, 2018 by Teachoo

Transcript

Example 6 Find the dimensions of the prayer hall discussed in Section 4.1. Suppose a charity trust decides to build a prayer hall having a carpet area of 300 square metres with its length one metre more than twice its breadth. What should be the length and breadth of the hall? We know that Area of hall = Length breadth Given area of hall = 300 m2 Also, length is one metre more than twice its breadth Let Breadth of the hall = x metres. Length of hall = (2x + 1) metres. Now, Area of hall = Length breadth 300 = (2x + 1) 300 = 2x2 + x 0 = 2x2 + x 300 2x2 + x 300 = 0 We factorize by splitting the middle term method 2x2 + 25 x 24x 300 = 0 x (2x + 25) 12 (2x + 25) = 0 (2x + 25) (x 12) = 0 Hence x = ( 25)/2 and x = 12 But x cannot be negative as number of breadth cannot be negative So, x = 12 Breadth of the hall = x = 12 m & Length of the hall = 2x + 1 = 2 (12) + 1 = 25 m

Solving by Splitting the middle term - Statement given

Chapter 4 Class 10 Quadratic Equations

Concept wise

- Checking quadratic equation
- Making quadratic equation
- Solving by Splitting the middle term - Equation given
- Solving by Splitting the middle term - Statement given
- Solving by completing square
- Nature of roots
- Solving by quadratic formula - Equation given
- Solving by quadratic formula - Equation to be formed

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.