Chapter 8 Class 9 Quadrilaterals
Serial order wise

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Ex 8.2, 7 ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that D is the mid-point of AC Given: ABC is right angled triangle, C = 90 M is the mid-point of AB, MD BC To prove: D is mid-point of AC, i.e., AD = CD Proof: In ABC, M is the mid-point of AB and MD BC. D is the mid-point of AC. Ex 8.2, 7 ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that (ii) MD AC As MD BC & AC is transversal MDC + BCD = 180 MDC + 90 = 180 MDC = 90 MD AC Hence proved Ex 8.2, 7 ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that (iii) CM = MA = 1/2 AB Join MC. In AMD and CMD, AD = CD ADM = CDM DM = DM AMD CMD AM = CM However, AM = 1/2 AB From (1) & (2) CM = AM = 1/2 AB

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo