1. Chapter 8 Class 9 Quadrilaterals
  2. Serial order wise
  3. Theorems

Theorem 8.1 - Chapter 8 Class 9 Quadrilaterals

Last updated at May 29, 2018 by

Theorem 8.1 - Class 9 - Diagonal of parallelogram divides.jpg

2 Theorem 8.1 - In ABC & ADC ASA congruency Hence Proved.jpg

 

Subscribe to our Youtube Channel - https://you.tube/teachoo

  1. Chapter 8 Class 9 Quadrilaterals
  2. Serial order wise

    3. Theorems

    Previous topics →

Transcript

Theorem 8.1: A diagonal of a parallelogram divides it into two congruent triangles Given: A parallelogram ABCD with AC as its diagonal To prove: ΔABC ≅ ΔADC Proof: Opposite sides of parallelogram is parallel So, AB ∥ DC and AD‖∥ BC In Δ ABC & Δ ADC ∠ BAC = ∠ DCA AC = AC ∠ DAC = ∠ BCA ∴ ΔABC ≅ ΔADC Hence proved

Chapter 8 Class 9 Quadrilaterals
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.