1. Chapter 8 Class 9 Quadrilaterals
  2. Serial order wise
  3. Theorems

Theorem 8.1

Last updated at Nov. 23, 2017 by

Theorem 8.1 - Class 9 - Diagonal of parallelogram divides.jpg

2 Theorem 8.1 - In ABC & ADC ASA congruency Hence Proved.jpg

 

  1. Chapter 8 Class 9 Quadrilaterals
  2. Serial order wise
    3. Theorems
    Concept wise →
Ask Download

Transcript

Theorem 8.1: A diagonal of a parallelogram divides it into two congruent triangles Given: A parallelogram ABCD with AC as its diagonal To prove: ΔABC ≅ ΔADC Proof: Opposite sides of parallelogram is parallel So, AB ∥ DC and AD‖∥ BC In Δ ABC & Δ ADC ∠ BAC = ∠ DCA AC = AC ∠ DAC = ∠ BCA ∴ ΔABC ≅ ΔADC Hence proved

Chapter 8 Class 9 Quadrilaterals
Serial order wise

About the Author

CA Maninder Singh's photo - Expert in Practical Accounts, Taxation and Efiling
CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .
Jail