Theorem 8.1 - Class 9 - Diagonal of parallelogram divides.jpg

Advertisement

Theorem 8.1 - Chapter 8 Class 9 Quadrilaterals - Part 2

Advertisement

 

  1. Chapter 8 Class 9 Quadrilaterals (Term 2)
  2. Serial order wise

Transcript

Theorem 8.1: A diagonal of a parallelogram divides it into two congruent triangles Given: A parallelogram ABCD with AC as its diagonal To prove: ΔABC ≅ ΔADC Proof: Opposite sides of parallelogram is parallel So, AB ∥ DC and AD‖∥ BC In Δ ABC & Δ ADC ∠ BAC = ∠ DCA AC = AC ∠ DAC = ∠ BCA ∴ ΔABC ≅ ΔADC Hence proved

About the Author

Davneet Singh's photo - Teacher, Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.