Theorem 8.1:
A diagonal of a parallelogram divides it into two congruent triangles
Given: A parallelogram ABCD
with AC as its diagonal
To prove: ΔABC ≅ ΔADC
Proof:
Opposite sides of parallelogram is parallel
So, AB ∥ DC and AD‖∥ BC
In Δ ABC & Δ ADC
∠ BAC = ∠ DCA
AC = AC
∠ DAC = ∠ BCA
∴ ΔABC ≅ ΔADC
Hence proved

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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