1. Chapter 8 Class 9 Quadrilaterals
  2. Serial order wise
  3. Theorems

Theorem 8.6 - Chapter 8 Class 9 Quadrilaterals

Last updated at May 29, 2018 by

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Theorem 8.6 - Class 9 - Diagonals of parallelogram bisect each other.jpg

2 Theorem 8.6 - So OA = OC & OB = OD (CPCT) Hence Proved.jpg

  1. Chapter 8 Class 9 Quadrilaterals
  2. Serial order wise

    3. Theorems

    Previous topics →

Transcript

Theorem 8.6 The diagonals of a parallelogram bisect each other Given : ABCD is a Parallelogram with AC and BD diagonals & O is the point of intersection of AC and BD To Prove : OA = OC & OB = OD Proof : Since, opposite sides of Parallelogram are parallel. In AOD and BOC OAD = OCB AD = CB ODA = OBC AOD BOC So, OA = OC & OB = OD Hence Proved

Chapter 8 Class 9 Quadrilaterals
Serial order wise

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