Theorem 8.6 - Chapter 8 Class 9 Quadrilaterals

Last updated at Dec. 16, 2024 by

Theorem 8.6 - Class 9 - Diagonals of a parallelogram bisect each other - Theorems

part 2 - Theorem 8.6 - Theorems - Serial order wise - Chapter 8 Class 9 Quadrilaterals

 

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Theorem 8.6 The diagonals of a parallelogram bisect each other Given : ABCD is a Parallelogram with AC and BD diagonals & O is the point of intersection of AC and BD To Prove : OA = OC & OB = OD Proof : Since, opposite sides of Parallelogram are parallel. In AOD and BOC OAD = OCB AD = CB ODA = OBC AOD BOC So, OA = OC & OB = OD Hence Proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo