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Theorem 8.6 - Chapter 8 Class 9 Quadrilaterals (Term 2)

Last updated at March 23, 2023 by

Theorem 8.6 - Class 9 - Diagonals of parallelogram bisect each other.jpg

Theorem 8.6 - Chapter 8 Class 9 Quadrilaterals - Part 2

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Theorem 8.6 The diagonals of a parallelogram bisect each other Given : ABCD is a Parallelogram with AC and BD diagonals & O is the point of intersection of AC and BD To Prove : OA = OC & OB = OD Proof : Since, opposite sides of Parallelogram are parallel. In AOD and BOC OAD = OCB AD = CB ODA = OBC AOD BOC So, OA = OC & OB = OD Hence Proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.