1. Chapter 8 Class 9 Quadrilaterals
  2. Serial order wise
  3. Theorems

Theorem 8.2 - Chapter 8 Class 9 Quadrilaterals

Last updated at May 29, 2018 by

Theorem 8.2 - Class 9 - In parallelogram, opposite sides are equal.jpg

2 Theorem 8.2 - Class 9 - Hence AB = CD & ADD = BC Hence Proved.jpg

  1. Chapter 8 Class 9 Quadrilaterals
  2. Serial order wise

    3. Theorems

    Previous topics →

Transcript

Theorem 8.2: In a parallelogram, opposite sides are equal. Given: A parallelogram ABCD with AC as its diagonal To prove: ΔABC ≅ ΔADC Proof: Opposite sides of parallelogram is parallel So, AB ∥ DC and AD‖∥ BC In Δ ABC & Δ ADC ∠ BAC = ∠ DCA AC = AC ∠ DAC = ∠ BCA ∴ ΔABC ≅ ΔADC Hence, AB = CD & AD = BC Hence proved

Chapter 8 Class 9 Quadrilaterals
Serial order wise

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.